Electronics - Number Systems and Codes - Discussion
Discussion Forum : Number Systems and Codes - General Questions (Q.No. 12)
12.
3428 is the decimal value for which of the following binary coded decimal (BCD) groupings?
Discussion:
9 comments Page 1 of 1.
Susheela said:
4 years ago
Given 3428
Follow the rule 8421.
According to that;
3 = 0011.
4=0100.
2= 0010.
8= 1000.
By combining these binary digits we get 0011010000101000. By eliminating the first 2 zeros we get 11010000101000.
Follow the rule 8421.
According to that;
3 = 0011.
4=0100.
2= 0010.
8= 1000.
By combining these binary digits we get 0011010000101000. By eliminating the first 2 zeros we get 11010000101000.
(1)
Pravallika said:
6 years ago
For every single digit we should use only 4 bits individually.
Here they had given 3248.
For 3 the binary is 0011,
4 means 0100,
2 means 0010,
8 means 1000,
Totally 0011 0100 0010 1000,
Then, it becomes 11010000101000.
Here they had given 3248.
For 3 the binary is 0011,
4 means 0100,
2 means 0010,
8 means 1000,
Totally 0011 0100 0010 1000,
Then, it becomes 11010000101000.
Mahendra said:
7 years ago
How the correct option is "B"?
Answer is 110101100100.
Answer is 110101100100.
(1)
Ankit Joshi said:
7 years ago
The answer is 110101100100.
(1)
P@$hooo said:
8 years ago
Please give me more explanation for the solution.
Ben said:
9 years ago
Convert each digit in 3428 to binary:
3=0011.
4=0100.
2=0010.
8=1000.
3=0011.
4=0100.
2=0010.
8=1000.
Stephen said:
9 years ago
Please I need more explanation.
Mounika said:
9 years ago
How you get that answer please clarify me clearly?
Sundar said:
1 decade ago
3428 (decimal) = 0011 0100 0010 1000 (binary)
= 11 0100 0010 1000 (binary)
So answer is option B.
= 11 0100 0010 1000 (binary)
So answer is option B.
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