# Electronics - Number Systems and Codes - Discussion

### Discussion :: Number Systems and Codes - General Questions (Q.No.12)

12.

3428 is the decimal value for which of the following binary coded decimal (BCD) groupings?

 [A]. 11010001001000 [B]. 11010000101000 [C]. 011010010000010 [D]. 110100001101010

Explanation:

No answer description available for this question.

 Sundar said: (Mar 11, 2011) 3428 (decimal) = 0011 0100 0010 1000 (binary) = 11 0100 0010 1000 (binary) So answer is option B.

 Mounika said: (Jul 9, 2015) How you get that answer please clarify me clearly?

 Stephen said: (Oct 12, 2015) Please I need more explanation.

 Ben said: (Nov 14, 2015) Convert each digit in 3428 to binary: 3=0011. 4=0100. 2=0010. 8=1000.

 P@\$Hooo said: (Oct 19, 2016) Please give me more explanation for the solution.

 Ankit Joshi said: (Oct 17, 2017) The answer is 110101100100.

 Mahendra said: (Dec 29, 2017) How the correct option is "B"? Answer is 110101100100.

 Pravallika said: (Aug 26, 2018) For every single digit we should use only 4 bits individually. Here they had given 3248. For 3 the binary is 0011, 4 means 0100, 2 means 0010, 8 means 1000, Totally 0011 0100 0010 1000, Then, it becomes 11010000101000.

 Susheela said: (Dec 2, 2020) Given 3428 Follow the rule 8421. According to that; 3 = 0011. 4=0100. 2= 0010. 8= 1000. By combining these binary digits we get 0011010000101000. By eliminating the first 2 zeros we get 11010000101000.