Electronics - Number Systems and Codes - Discussion

12. 

3428 is the decimal value for which of the following binary coded decimal (BCD) groupings?

[A]. 11010001001000
[B]. 11010000101000
[C]. 011010010000010
[D]. 110100001101010

Answer: Option B

Explanation:

No answer description available for this question.

Sundar said: (Mar 11, 2011)  
3428 (decimal) = 0011 0100 0010 1000 (binary)

= 11 0100 0010 1000 (binary)

So answer is option B.

Mounika said: (Jul 9, 2015)  
How you get that answer please clarify me clearly?

Stephen said: (Oct 12, 2015)  
Please I need more explanation.

Ben said: (Nov 14, 2015)  
Convert each digit in 3428 to binary:

3=0011.
4=0100.
2=0010.
8=1000.

P@$Hooo said: (Oct 19, 2016)  
Please give me more explanation for the solution.

Ankit Joshi said: (Oct 17, 2017)  
The answer is 110101100100.

Mahendra said: (Dec 29, 2017)  
How the correct option is "B"?

Answer is 110101100100.

Pravallika said: (Aug 26, 2018)  
For every single digit we should use only 4 bits individually.

Here they had given 3248.
For 3 the binary is 0011,
4 means 0100,
2 means 0010,
8 means 1000,
Totally 0011 0100 0010 1000,
Then, it becomes 11010000101000.

Susheela said: (Dec 2, 2020)  
Given 3428

Follow the rule 8421.
According to that;
3 = 0011.
4=0100.
2= 0010.
8= 1000.

By combining these binary digits we get 0011010000101000. By eliminating the first 2 zeros we get 11010000101000.

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