Electronics - Number Systems and Codes - Discussion
Discussion Forum : Number Systems and Codes - General Questions (Q.No. 11)
11.
What is the resultant binary of the decimal problem 49 + 1 = ?
Discussion:
12 comments Page 1 of 2.
Pankaj said:
1 decade ago
How?
Vidhya UTL said:
1 decade ago
How it's possible ?
Narendra said:
1 decade ago
49=110001
1=1
49+1= 110001+1
110010
1=1
49+1= 110001+1
110010
Rupa said:
1 decade ago
Ya Narendra said is correct.
Mani said:
1 decade ago
Please explain me.
Pachai said:
1 decade ago
2| 49
2| 24 1
2| 12 0
2| 6 0
2| 3 0
1 1
(49)10=(110001)2
(1)10=(1)2
49 00110001
1 00000001
00110010
(or)
49+1=50
(50)10=(00110010)2
2| 24 1
2| 12 0
2| 6 0
2| 3 0
1 1
(49)10=(110001)2
(1)10=(1)2
49 00110001
1 00000001
00110010
(or)
49+1=50
(50)10=(00110010)2
B.malathi said:
1 decade ago
49=110001
1=1
110001
1(+)
110010
1=1
110001
1(+)
110010
Komali said:
1 decade ago
49+1=50. Decimal 50 is divided by binary 2. Result was 110010. Since a BCD can store a 4 bit. So we are adding 00 to MSB. Result is 00110010.
Bhaskar said:
1 decade ago
'49' binary equivalent is 110001.
'1' binary equivalent is 000001.
After binary addition = 110010.
'1' binary equivalent is 000001.
After binary addition = 110010.
Jamuna said:
10 years ago
Why you can't take 49+1 =50 directly?
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