Electronics - Magnetism and Electromagnetism - Discussion
Discussion Forum : Magnetism and Electromagnetism - Filling the Blanks (Q.No. 2)
2.
The flux density is ___ when the magnetic flux is 9 µWb and the cross-sectional area of the magnetic field is 5 × 10–3 m2.
Discussion:
3 comments Page 1 of 1.
Durga said:
1 decade ago
Flux = flux density*area of cross section.
Flux density = 9/5*10^-3 = 1800.
Flux density = 9/5*10^-3 = 1800.
Katlego said:
9 years ago
Please explain it more.
Farhan said:
3 years ago
It's formula based.
The Magnetic Flux "Density" is denoted as;
Beta(β)[unit T(tesla)].
and Magnetic Flux is denoted as;
Phi(φ)[unit Wb(weber) ].
The Formula β=φ/A.
(Flux Density equals Flux all over Area.)
Thus:
β = (9x10^-6)/(5x10^-3).
β = 1.8mT or 1800μT.
The Magnetic Flux "Density" is denoted as;
Beta(β)[unit T(tesla)].
and Magnetic Flux is denoted as;
Phi(φ)[unit Wb(weber) ].
The Formula β=φ/A.
(Flux Density equals Flux all over Area.)
Thus:
β = (9x10^-6)/(5x10^-3).
β = 1.8mT or 1800μT.
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