Electronics - Magnetism and Electromagnetism - Discussion

4. 

How much flux is there in a magnetic field when its flux density is 5000 mu.gifT and its cross-sectional area is 300 mm2?

[A]. 16.67 mWb
[B]. 5.0 mu.gifWb
[C]. 3.0 mWb
[D]. 1.5 mu.gifWb

Answer: Option D

Explanation:

No answer description available for this question.

Rahul said: (Aug 16, 2011)  
B=U*H
5000*300=1500000
=1.5UWb

Chetan said: (Sep 16, 2012)  
U is permeability,
fi=b*a;
b=flux density;
a=cross sec area

Sharad said: (Oct 11, 2012)  
U is permeability,
fi=b*a;
b=flux density;
a=cross sec area
B=U*H
5000*300=1500000
=1.5UWb.

Teerthram Meena said: (Feb 6, 2014)  
We now that magnetic flux is equal to product of flux density and cross sectional area so flux density is 1.5 micro Weber.

Luv said: (Aug 3, 2014)  
Given B = 5000 micro Tesla = 50 Gauss.
A = 300mm^2 = 3*10^(-4) m^2.

Flux = B.A = 50* .0003 = .015 Wb.

Manoj said: (Jan 30, 2015)  
Flux = Flux density*area.

Flux = 5000*10^-6*300*10^-6 = 1.5 micro weber.

Ajith said: (Aug 21, 2015)  
What is microweber explain please?

Pankaj said: (Jan 28, 2019)  
B = fluxe*area.
B = 5000*10^-6,
A = 300÷10^3.

5000*300*10^-9 = 15 ÷ 10^4 = .0015web.

Kelvin G said: (Mar 11, 2019)  
flux density = flux/area.
flux=flux density * -area,
= 5000uT * (300 * 10^-6)m2.
= 1.5.

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