Electronics - Magnetism and Electromagnetism - Discussion
Discussion Forum : Magnetism and Electromagnetism - General Questions (Q.No. 4)
4.
How much flux is there in a magnetic field when its flux density is 5000 
T and its cross-sectional area is 300 mm2?
T and its cross-sectional area is 300 mm2?16.67 mWb
5.0 Wb
Wb3.0 mWb
1.5 Wb
WbDiscussion:
9 comments Page 1 of 1.
Kelvin G said:
6 years ago
flux density = flux/area.
flux=flux density * -area,
= 5000uT * (300 * 10^-6)m2.
= 1.5.
flux=flux density * -area,
= 5000uT * (300 * 10^-6)m2.
= 1.5.
Pankaj said:
6 years ago
B = fluxe*area.
B = 5000*10^-6,
A = 300÷10^3.
5000*300*10^-9 = 15 ÷ 10^4 = .0015web.
B = 5000*10^-6,
A = 300÷10^3.
5000*300*10^-9 = 15 ÷ 10^4 = .0015web.
Ajith said:
9 years ago
What is microweber explain please?
Manoj said:
1 decade ago
Flux = Flux density*area.
Flux = 5000*10^-6*300*10^-6 = 1.5 micro weber.
Flux = 5000*10^-6*300*10^-6 = 1.5 micro weber.
Luv said:
1 decade ago
Given B = 5000 micro Tesla = 50 Gauss.
A = 300mm^2 = 3*10^(-4) m^2.
Flux = B.A = 50* .0003 = .015 Wb.
A = 300mm^2 = 3*10^(-4) m^2.
Flux = B.A = 50* .0003 = .015 Wb.
Teerthram meena said:
1 decade ago
We now that magnetic flux is equal to product of flux density and cross sectional area so flux density is 1.5 micro Weber.
Sharad said:
1 decade ago
U is permeability,
fi=b*a;
b=flux density;
a=cross sec area
B=U*H
5000*300=1500000
=1.5UWb.
fi=b*a;
b=flux density;
a=cross sec area
B=U*H
5000*300=1500000
=1.5UWb.
Chetan said:
1 decade ago
U is permeability,
fi=b*a;
b=flux density;
a=cross sec area
fi=b*a;
b=flux density;
a=cross sec area
RAHUL said:
1 decade ago
B=U*H
5000*300=1500000
=1.5UWb
5000*300=1500000
=1.5UWb
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