# Electronics - Magnetism and Electromagnetism - Discussion

### Discussion :: Magnetism and Electromagnetism - General Questions (Q.No.4)

4.

How much flux is there in a magnetic field when its flux density is 5000 T and its cross-sectional area is 300 mm2?

 [A]. 16.67 mWb [B]. 5.0 Wb [C]. 3.0 mWb [D]. 1.5 Wb

Explanation:

No answer description available for this question.

 Rahul said: (Aug 16, 2011) B=U*H 5000*300=1500000 =1.5UWb

 Chetan said: (Sep 16, 2012) U is permeability, fi=b*a; b=flux density; a=cross sec area

 Sharad said: (Oct 11, 2012) U is permeability, fi=b*a; b=flux density; a=cross sec area B=U*H 5000*300=1500000 =1.5UWb.

 Teerthram Meena said: (Feb 6, 2014) We now that magnetic flux is equal to product of flux density and cross sectional area so flux density is 1.5 micro Weber.

 Luv said: (Aug 3, 2014) Given B = 5000 micro Tesla = 50 Gauss. A = 300mm^2 = 3*10^(-4) m^2. Flux = B.A = 50* .0003 = .015 Wb.

 Manoj said: (Jan 30, 2015) Flux = Flux density*area. Flux = 5000*10^-6*300*10^-6 = 1.5 micro weber.

 Ajith said: (Aug 21, 2015) What is microweber explain please?

 Pankaj said: (Jan 28, 2019) B = fluxe*area. B = 5000*10^-6, A = 300÷10^3. 5000*300*10^-9 = 15 ÷ 10^4 = .0015web.

 Kelvin G said: (Mar 11, 2019) flux density = flux/area. flux=flux density * -area, = 5000uT * (300 * 10^-6)m2. = 1.5.