Discussion :: Logic Circuit Simplification - General Questions (Q.No.9)
|Sooryashibu said: (Feb 25, 2014)|
|NAND = NOT of AND.|
|Lakshmi said: (Apr 21, 2015)|
|Can you please elaborate?|
|Abedelkareem said: (Jul 11, 2015)|
|I think that, the correct answer is D.
Because a NAND is equivalent to after equal term and OR with bubbled output is equivalent for the before equal term.
|Scaneu said: (Aug 31, 2016)|
|I think it should be: OR gate with bubble on each input is equivalent to a NAND gate.|
|Mohan said: (Jun 11, 2017)|
|Option B is Correct.
A NOR gate and a bubbled input of AND gate.
|Madarasi said: (Jun 11, 2017)|
|I think option A is correct.
Because, NAND gate output=A.B whole bar=A bar+B bar.
The Output of AND gate is A.B = bubbled output=A.B whole bar.
|Affan said: (Mar 17, 2018)|
|Option A is correct.
As ( A.B whole bar = Abar + Bbar) is the result of only NAND gate.
Therefore option A as both gates are NAND in this option only.
|Sneha said: (Jan 15, 2019)|
|I think Option D is correct.
As (A.B whole bar = Abar + Bbar) is the result of only NAND gate and (Abar + Bbar=bubbled OR).
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