Electronics - Inductors - Discussion
Discussion Forum : Inductors - General Questions (Q.No. 64)
64.
You could decrease the time constant of an RL circuit by
Discussion:
7 comments Page 1 of 1.
Alia said:
5 years ago
If we decrease input voltage consequently L decreases,
V= Ldi/dt and hence T decreases.
So option C is correct.
V= Ldi/dt and hence T decreases.
So option C is correct.
Amit said:
8 years ago
Time constant: L/R.
We have two approaches for decreasing time constant ,
1) decrease L by adding parallel inductance,
2) increase R by adding series resistance,
We have two approaches for decreasing time constant ,
1) decrease L by adding parallel inductance,
2) increase R by adding series resistance,
Jude said:
8 years ago
How come the inductance will decrease by adding an inductor in series?
Arvind said:
9 years ago
If we take the case of option A then by adding a resistance in parallel will decrease the resistance and ultimately increase the time constant. As, Time Constant is inversely proportional to are. This is why option B is correct.
@Awadhesh is correct.
@Awadhesh is correct.
Awadhesh bettiah said:
1 decade ago
If you add inductor in series and then you have to go for procedure to find time constant. So in that procedure you have to short voltage source and finally inductor will comes parallel and equivalent inductance will reduce.
Adco said:
1 decade ago
Why is the answer is increasing the inductor if formula of time constant is L/R?
Deepayan said:
1 decade ago
T.C. of a RL circuit = L / R.
So to decrease T.C., we can decrease L or we can increase R.
Option A decreases overall R.
Option B increases overall L.
So How is option B correct?
So to decrease T.C., we can decrease L or we can increase R.
Option A decreases overall R.
Option B increases overall L.
So How is option B correct?
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