Electronics - Inductors - Discussion
Discussion Forum : Inductors - General Questions (Q.No. 22)
22.
What is the inductive reactance if the Q of a coil is 60, and the winding resistance is 5 
?
?0.083
12
30
300
Discussion:
7 comments Page 1 of 1.
Nagashree said:
1 decade ago
We know that, Q=Xl/R
So Xl = Q*R = 60*5 = 300 Ohms.
So Xl = Q*R = 60*5 = 300 Ohms.
Alex said:
1 decade ago
I think this is incorrect.
In fact:
Q=L/R.
Xl is a dynamic opposition to current flow in an inductor related to frequency.
The question should ask: "What is the inductance".
And the answer should be listed in H (Henry).
In fact:
Q=L/R.
Xl is a dynamic opposition to current flow in an inductor related to frequency.
The question should ask: "What is the inductance".
And the answer should be listed in H (Henry).
Chauhan Parth said:
10 years ago
Q = L/R.
= 60/5.
= 12.
= 60/5.
= 12.
Abdullah said:
9 years ago
Solution:
Q = L/R
than L = q*r
L = 60 * 5 = 300.
Q = L/R
than L = q*r
L = 60 * 5 = 300.
Nimeshpatel said:
9 years ago
L = QR.
So, the answer is 300.
So, the answer is 300.
Pritam said:
5 years ago
Q = Xl/R.
Xl = 60*5=300;
Xl = inductive reactance.
Q = quality factor.
Note: T= L/R.
Xl = 60*5=300;
Xl = inductive reactance.
Q = quality factor.
Note: T= L/R.
Shivananda said:
4 years ago
Thanks for explaining the answer @Alex.
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