Electronics - Inductors - Discussion
Discussion Forum : Inductors - General Questions (Q.No. 57)
57.
What is the current rise after 2 time constants if Vs = 12 V dc, R = 60 
, and the inductor is rated at 24 mH?
, and the inductor is rated at 24 mH?Discussion:
8 comments Page 1 of 1.
Syed Shakeeb said:
4 years ago
'e' exponential means increasing more and more at a short time at a great rate.
E.SAE said:
9 years ago
@Sivapramod.
e means exponential
e means exponential
E.SAE said:
9 years ago
@Sivapramod.
e means exponential
e means exponential
SIVAPRAMOD said:
9 years ago
What is the value of 'e' in the given formula?
Sanjoy said:
10 years ago
Current rise after 2 time constant.
So, IL = I(1-e^-2).
IL = 0.2 (1-0.13) = 173 mA.
So, IL = I(1-e^-2).
IL = 0.2 (1-0.13) = 173 mA.
Sajid said:
1 decade ago
I = It*(e^(-2))
It=Vs/Z
Z=(R^2+Xl^2)^1/2
Xl=2*3.14*f*L /// f=0,Since DC ///
Z = R
It = Vs/R
=12/60
=.2
Now,
I = .2(e^(-2))
= .1729
=173mA
It=Vs/Z
Z=(R^2+Xl^2)^1/2
Xl=2*3.14*f*L /// f=0,Since DC ///
Z = R
It = Vs/R
=12/60
=.2
Now,
I = .2(e^(-2))
= .1729
=173mA
Prasanna said:
1 decade ago
R + jXL= sqrt( 60^2 + 24^2 )
I = Vs/(R+ jXL)
2t=.862
I at 2t is = I*0.862
I = Vs/(R+ jXL)
2t=.862
I at 2t is = I*0.862
Chaitali Acharya said:
1 decade ago
Please could anyone give a formula for this question?
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