Electronics - Inductors - Discussion
Discussion Forum : Inductors - General Questions (Q.No. 30)
30.
If the switch is moved to position 1 in the given circuit, how long will it take for the current to reach its maximum value?
72.5 
s
s532 s
s610 s
s833 s
sDiscussion:
8 comments Page 1 of 1.
Pritam said:
5 years ago
At position 2 inductor is discharging.
Before coming to position 1 inductor is completely discharged.
Its general formula for complete charging of capacitor and inductor 5T.
5*L/R=5*0.1/940=532us.
Before coming to position 1 inductor is completely discharged.
Its general formula for complete charging of capacitor and inductor 5T.
5*L/R=5*0.1/940=532us.
Balu said:
8 years ago
Because the current will have reached 99.5% of the steady state value after 5 time constants.
Yateesh kumar vc said:
9 years ago
On which basis t is multiplied by 5. I didn't please solve this problem.
Tushar Sharma said:
1 decade ago
Time constant for LR circuit is t = L/R.
Now R=120+820 = 940R.
L = 100mH.
So t = L/R
=0.1063829ms.
To reach maximum i.e. 100% value; it will take 5 time constants,
5 Time constants.
1T 63.2%
2T 86.4%
3T 94.9%
4T 98.1%
5T 100%
So,
T = 5*0.1063829ms = 532us.
Now R=120+820 = 940R.
L = 100mH.
So t = L/R
=0.1063829ms.
To reach maximum i.e. 100% value; it will take 5 time constants,
5 Time constants.
1T 63.2%
2T 86.4%
3T 94.9%
4T 98.1%
5T 100%
So,
T = 5*0.1063829ms = 532us.
Kiran said:
1 decade ago
How we had taken resistance value?
Priya said:
1 decade ago
Time constant for RL circuit is t = L/R
t=0.1/940=0.1063829ms
5 time time constants it will to reach its max value. t = 5*0.1063829ms = 532 us.
t=0.1/940=0.1063829ms
5 time time constants it will to reach its max value. t = 5*0.1063829ms = 532 us.
Rashid call3135791000 said:
1 decade ago
It is RL circuit, we use Vs=R + Inductor.
Prudvi said:
1 decade ago
Please tel me how to solve it!
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