Electronics - Inductors - Discussion

10. 

What is the total inductance in the given circuit?

[A]. 160 mH
[B]. 300 mH
[C]. 900 mH
[D]. 1700 mH

Answer: Option A

Explanation:

No answer description available for this question.

Gjhoj said: (Nov 9, 2011)  
1/600+1/300+1/800
.006+.003+.008

Tejas Savani said: (Apr 6, 2012)  
Total= 1/[(1/L1) + (1/L2) + (1/L3)]
= 1/0.00625
= 160 mH

Diwakar said: (Apr 23, 2012)  
1/Ltotal =1/L1+1/L2+1/L3

=1/600+1/300+1/800
=15/2400

L =2400/15
=160

Jayashri said: (Feb 5, 2014)  
How comes that answer, please tel me I have doubt why are you taken 15 number in calculation.

Jeya said: (Feb 20, 2014)  
Hi @Jayashri 15 is nothing but just he taken LCM.

1/Ltotal = 1/L1+1/L2+1/L3.
= 1/300+1/600+1/800.

LCM of denominator is 2400.
Above equation becomes,

1/Ltotal = (8+4+3)/2400 = 15/2400.
1/Ltotal = 15/2400.
Ltotal = 2400/15 = 160.

Anjali said: (Apr 24, 2016)  
Why are you taking 15 number for calculation?

Shaheer said: (Aug 25, 2016)  
Hi @Anjali.

Formulae for inductance L.
1/L = 1/L1 + 1/L2 + 1/L3.

Therefore substituting the given values in formulae,
1/L = 1/600 + 1/300 + 1/800.
L.C.M of 600, 300, 800 is 2400.

SO
1/L = 4/2400 + 8/2400 + 3/2400.
1/L = 15/2400.

THEREFORE L = 2400/15.
= 160 -> Answer

Sanjay said: (Dec 2, 2016)  
Without mutual induction magnitude. How this could be possible?

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