Electronics - Inductors - Discussion

91. 

What is the phase angle between the source voltage and current, when a 100 mH inductor with a reactance of 6 komega.gif, and a 1 komega.gif resistor are in series with a source?

[A]. 0.1 degrees
[B]. 9.0 degrees
[C]. 61.0 degrees
[D]. 81.0 degrees

Answer: Option D

Explanation:

No answer description available for this question.

Navdeep said: (Aug 1, 2013)  
How is that found? May someone explain please?

Sameer said: (Oct 23, 2013)  
Since tan(angle) = Xl-Xc/R, here Xc is absent, therefore, tan(angle) = Xl/R.

i.e Angle = tan^-1(6)=80.5~81.0 degrees.

Abar -4744 said: (Oct 19, 2019)  
Tan(θ) = X/R.
Here,

X is reactance of nductance, R resistance in series.

Ali Gohar said: (Dec 7, 2019)  
tan(-1) 6 = 1.40.
How is 81 coming?

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