Electronics - Inductors - Discussion
Discussion Forum : Inductors - General Questions (Q.No. 85)
85.
What is the total inductance assuming no mutual inductance?
Discussion:
2 comments Page 1 of 1.
Shyam verma said:
1 decade ago
Total inductance in parallel(LT).
1/LT = 1/L1+1/L2+1/L3+1/L4.
1/87/60.
60/86 = 0.69mh.
1/LT = 1/L1+1/L2+1/L3+1/L4.
1/87/60.
60/86 = 0.69mh.
Savitha U.R said:
1 decade ago
Total inductance in parallel(LT)
1/LT=1/L1+1/L2+1/L3+1/L4
=(1/1+1/5+1/6+1/12)1/10^-3
=(1+0.2+0.1667+0.0175)10^3
1/LT=1.3842*10^3
LT=1/(1.3842*10^3)
=0.7224*10^-3
=0.72mH~~0.69mH
SO Ans is B.
1/LT=1/L1+1/L2+1/L3+1/L4
=(1/1+1/5+1/6+1/12)1/10^-3
=(1+0.2+0.1667+0.0175)10^3
1/LT=1.3842*10^3
LT=1/(1.3842*10^3)
=0.7224*10^-3
=0.72mH~~0.69mH
SO Ans is B.
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