Electronics - Inductors - Discussion

85. 

What is the total inductance assuming no mutual inductance?

mcq8_1031_1.gif

[A]. 0 mH
[B]. 0.69 mH
[C]. 12 mH
[D]. 24 mH

Answer: Option B

Explanation:

No answer description available for this question.

Savitha U.R said: (Apr 16, 2012)  
Total inductance in parallel(LT)

1/LT=1/L1+1/L2+1/L3+1/L4
=(1/1+1/5+1/6+1/12)1/10^-3
=(1+0.2+0.1667+0.0175)10^3
1/LT=1.3842*10^3
LT=1/(1.3842*10^3)
=0.7224*10^-3
=0.72mH~~0.69mH
SO Ans is B.

Shyam Verma said: (Jun 28, 2014)  
Total inductance in parallel(LT).

1/LT = 1/L1+1/L2+1/L3+1/L4.

1/87/60.

60/86 = 0.69mh.

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