Electronics - Field Effect Transistors (FET) - Discussion

Discussion Forum : Field Effect Transistors (FET) - General Questions (Q.No. 28)

Field Effect Transistors (FET)

28.

Using voltage-divider biasing, what is the voltage at the gate V_GS?

5.2 V

4.2 V

3.2 V

2.2 V

Answer: Option

Explanation:

No answer description is available. Let's discuss.

Discussion:

6 comments Page 1 of 1.

AMIT SONKAMBLE said: 9 years ago

Thanks for all to give the good explanation.

(1)

Louie said: 1 decade ago

V(GS)=V(DD)*R2/(R1+R2)
Where V(GS)= V(in)
V(DD) = VCC

(1)

Jadeep said: 1 decade ago

i=20/23k
i=0.826
v=0.826*6=5.2

Jayalakshmi said: 1 decade ago

V(GS)=V(DD)*R2/(R1+R2)

Jayalakshmi said: 1 decade ago

V(R2)=V(GS)=V(DD)*R2/R1

Doudi amine said: 2 decades ago

i didn't get any help tp figure out how does it realy can be solve

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