Electronics - Diodes and Applications - Discussion
Discussion Forum : Diodes and Applications - General Questions (Q.No. 32)
32.
If the frequency of the applied ac signal to a half-wave rectifier is 60 Hz, the frequency of the pulsating dc output will be
Discussion:
3 comments Page 1 of 1.
Wahab said:
1 decade ago
Vs/Vp=Ns/Np
Vs=169.706*1/20
Vs=8.485v
peak output voltage=Vs-0.7=7.78v
Vs=169.706*1/20
Vs=8.485v
peak output voltage=Vs-0.7=7.78v
(1)
Gayatri said:
1 decade ago
The frequency of the output voltage is equal to the frequency of the applied ac signal since there is one pulse out for each cycle of the ac input (60 Hz). Therefore output dc pulsating voltage contains 60pps (pulse per sec).
(1)
Mrs. Smita mam said:
1 decade ago
Frequency remains same for input and output so answer is 60pps.
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