Electronics - Diodes and Applications - Discussion
Discussion Forum : Diodes and Applications - Filling the Blanks (Q.No. 2)
2.
The average value of the half-wave rectified output voltage is approximately __________ of Vp.
Discussion:
3 comments Page 1 of 1.
Historia said:
4 years ago
Vdc or Vave = Vp/T for a HW rectifier.
Therefore Vdc = (0.31831)Vp = 31.1831% of Vpeak.
Therefore Vdc = (0.31831)Vp = 31.1831% of Vpeak.
Mubashir Tanveer said:
5 years ago
@Ayaz.
We just have Vp, or Vmax (Vm).
Vavg=1/T integral Pi to 0 Vmsin wt dt (v average is equal to 1/t its cycle integral limits π to 0 t max or V Peek sin omega t derivate with respect to d).
= Vp/T ( -COSwt/w)limit T/2 to 0.
or simple is that Vavg=Vm/π.
We just have Vp, or Vmax (Vm).
Vavg=1/T integral Pi to 0 Vmsin wt dt (v average is equal to 1/t its cycle integral limits π to 0 t max or V Peek sin omega t derivate with respect to d).
= Vp/T ( -COSwt/w)limit T/2 to 0.
or simple is that Vavg=Vm/π.
Ayaz said:
7 years ago
Please explain it.
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