Electronics - Diodes and Applications - Discussion
Discussion Forum : Diodes and Applications - General Questions (Q.No. 33)
33.
What is the peak output voltage for this half-wave rectifier?
Discussion:
17 comments Page 2 of 2.
Mohamed said:
1 decade ago
What is the output characteristics ?
Ralph said:
1 decade ago
Yes, but voltage is always given as RMS unless otherwise stated, so the correct answer is not listed.
Vpk = 169.706Vrms / .707 = 240Vpk / 20 = 12Vpk - .7V = 11.3 Vpk.
Vpk = 169.706Vrms / .707 = 240Vpk / 20 = 12Vpk - .7V = 11.3 Vpk.
Ismail said:
1 decade ago
Vs/Vp=Ns/Np.
Vs=169.706*1/20.
Vs=8.485v.
Peak output voltage=Vs-0.7=7.78v.
Vs=169.706*1/20.
Vs=8.485v.
Peak output voltage=Vs-0.7=7.78v.
Alok kumar said:
1 decade ago
Diode is foreword biased practically no voltage drop across the diode but due to silicon or germanium diode 0.7v or 0.3v drop across the diode secondary voltage of the transformer is approximately 8.48 volts. But subtract the drop across the diode 0.7v =7.78 volts.
Prveen said:
1 decade ago
Is diode forward bias. ?
Nabhdeep chauhan said:
1 decade ago
v2= n2/n1*v1
=1/20*169.706
so v2=8.4853 volts
so output voltage will be 8.4853-0.7
Vo=7.7853
so option 'B' is correct 7.8 volts
=1/20*169.706
so v2=8.4853 volts
so output voltage will be 8.4853-0.7
Vo=7.7853
so option 'B' is correct 7.8 volts
Prashil & Vijay said:
1 decade ago
V2/V1 = N2/N1
V2 - voltage at secondary
V1 - voltage at primary
N2 - no of turns of secondary coil
N1 - no of turns of primary coil
V2 - voltage at secondary
V1 - voltage at primary
N2 - no of turns of secondary coil
N1 - no of turns of primary coil
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers