Electronics - Diodes and Applications - Discussion

Discussion Forum : Diodes and Applications - General Questions (Q.No. 33)
33.
What is the peak output voltage for this half-wave rectifier?

1 V
7.8 V
10.9 V
15.6 V
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
17 comments Page 1 of 2.

Syed Shakeeb said:   4 years ago
Thanks everyone for explaining.

Claude said:   4 years ago
@All.

If you draw the output waveform of the HW- RECTIFIER given an input of 8.485 V(since you don't really use the peak voltage value as an input but rather the rms value) the output WAVEFORM would have a peak of (8.485-0.7) = 7.8 V,

So, B would be correct.

ABC said:   4 years ago
Vpeak across the resistor is 11.3V.
Vrms is 7.78V, since it says Vpeak, therefore the answer is not listed.
(2)

Manoj said:   7 years ago
Right @Ralph.

RMS to v peak should v conversion.

Junior said:   7 years ago
V(sec)=n*V(pri).
V(sec)=1/20*169.706 ,
V (sec)=8.4853.

V(out)= V(sec) - 0.7.
=7.8v.

Gurpreet kaur said:   1 decade ago
1n 4001 diode is from silicon families. So it's a silicon diode.

MARKANDEPPA said:   1 decade ago
But they will not mention it's diode silicon or germanium, we should calculate as a ideal.

Shah said:   1 decade ago
From wahab, comment from previous question.
Vs/Vp = Ns/Np,

Vs = 169.706*1/20.
Vs = 8.485v.

Peak output voltage = Vs-0.7 = 7.78v.

Adco said:   1 decade ago
I agree with @Ralph. It is not indicated that it is vdc. You will always assume the source to be in RMS.

Mohamed said:   1 decade ago
What is the output characteristics ?


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