Electronics - Diodes and Applications - Discussion
Discussion Forum : Diodes and Applications - General Questions (Q.No. 33)
33.
What is the peak output voltage for this half-wave rectifier?
Discussion:
17 comments Page 2 of 2.
MARKANDEPPA said:
1 decade ago
But they will not mention it's diode silicon or germanium, we should calculate as a ideal.
Gurpreet kaur said:
1 decade ago
1n 4001 diode is from silicon families. So it's a silicon diode.
Junior said:
7 years ago
V(sec)=n*V(pri).
V(sec)=1/20*169.706 ,
V (sec)=8.4853.
V(out)= V(sec) - 0.7.
=7.8v.
V(sec)=1/20*169.706 ,
V (sec)=8.4853.
V(out)= V(sec) - 0.7.
=7.8v.
Manoj said:
7 years ago
Right @Ralph.
RMS to v peak should v conversion.
RMS to v peak should v conversion.
ABC said:
4 years ago
Vpeak across the resistor is 11.3V.
Vrms is 7.78V, since it says Vpeak, therefore the answer is not listed.
Vrms is 7.78V, since it says Vpeak, therefore the answer is not listed.
(2)
Claude said:
4 years ago
@All.
If you draw the output waveform of the HW- RECTIFIER given an input of 8.485 V(since you don't really use the peak voltage value as an input but rather the rms value) the output WAVEFORM would have a peak of (8.485-0.7) = 7.8 V,
So, B would be correct.
If you draw the output waveform of the HW- RECTIFIER given an input of 8.485 V(since you don't really use the peak voltage value as an input but rather the rms value) the output WAVEFORM would have a peak of (8.485-0.7) = 7.8 V,
So, B would be correct.
Syed Shakeeb said:
4 years ago
Thanks everyone for explaining.
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