Electronics - Diodes and Applications - Discussion

Discussion Forum : Diodes and Applications - General Questions (Q.No. 15)
15.
The peak inverse voltage (PIV) across a nonconducting diode in a bridge rectifier equals approximately:
half the peak secondary voltage
twice the peak secondary voltage
the peak value of the secondary voltage
four times the peak value of the secondary voltage
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
6 comments Page 1 of 1.

M.lakshmireddy said:   5 years ago
Option B is correct it is twice the secondary Voltage.

Lyna lopez said:   6 years ago
What if the question was.

The peak inverse voltage across a nonconducting diode in a unfiltered bridge rectifier equals approximately?

Mahichandu said:   1 decade ago
Ans C is right ,
# piv for half- wave rectifier is Vm
# full-wave rectifier is 2Vm
# bridge rectifier is Vm
Because which are the entire secondary voltage appears across the non-conducting diodes
As far question option C is correct.

Sandeep said:   1 decade ago
No the answer is right, for half wave rectifier, max voltage appearing across trnsfrmr secondary, for fulll wave it is 2*tnsfrmer secndry. For bridge it is max trnsfermer secndry voltage.

Mohan vinnakota said:   1 decade ago
Actually the answer is B. Because by using bridge configuration the PIV is increased twice.

Shalini said:   1 decade ago
I think the answer is B.

The diode has to withstand another peak voltage during the negative half cycle since the bridge rectifier is a full wave rectifier.

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