Electronics - Diodes and Applications - Discussion
Discussion Forum : Diodes and Applications - General Questions (Q.No. 36)
36.
What is the percent of regulation if Vnl = 20 V and Vfl = 19.8 V?
Discussion:
10 comments Page 1 of 1.
JYOTIRMOY MANTA said:
1 decade ago
RESULT,
Vnl=20 volt.
Vfl=19.8 volt.
SO, Percent of Regulation = (Vnl-Vfl/Vfl)*100.
= (20-19.8/19.8)*100.
= .2/19.8*100.
= 1%.
Vnl=20 volt.
Vfl=19.8 volt.
SO, Percent of Regulation = (Vnl-Vfl/Vfl)*100.
= (20-19.8/19.8)*100.
= .2/19.8*100.
= 1%.
Ambika kinni said:
1 decade ago
%regulation=(Vfl-Vnl)/Vfl
=(20-19.8)/20
=0.01*100
=1%
=(20-19.8)/20
=0.01*100
=1%
Dharani said:
8 years ago
% regulation= ((No load voltage-Full load voltage)/No load voltage) *100.
(2)
Ajay said:
1 decade ago
@Trisha Sen: Vnl is no-load voltage and vl is load voltage.
Pramod said:
1 decade ago
%regulation= (vnl-vl)/vl
=(20-19.8)/19.8
=1%
=(20-19.8)/19.8
=1%
Deepika said:
6 years ago
Noload - full load/full load * 100.
(1)
Prashant said:
10 years ago
= 20-19.8/20.
= 0.01*100 = 1%.
= 0.01*100 = 1%.
DAYO said:
9 years ago
((20 - 19.8)/20) * 100 = 1%.
Trisha sen said:
1 decade ago
What is Vn1 and Vf1?
Syed Shakeeb said:
4 years ago
Thank you, everyone.
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