Electronics - Diodes and Applications - Discussion

Discussion Forum : Diodes and Applications - General Questions (Q.No. 5)
The dc current through each diode in a bridge rectifier equals:
the load current
half the dc load current
twice the dc load current
one-fourth the dc load current
Answer: Option
No answer description is available. Let's discuss.
16 comments Page 1 of 2.

Thembs said:   1 decade ago
They are connected in parallel.

R.a.chaudhari said:   1 decade ago
They are connected in series.

PRADHEEP H N said:   1 decade ago
All diodes are connected in series with load so; in branch the current is same. ANS (A).

Ambrish Pandey said:   1 decade ago
All diodes are connected in series and in + forward bias diode is on and in - reverse bias diode is on. So in all cases the diode is in farword bias and it will open so it will equal to the load current.

Balwinder singh said:   1 decade ago
If we use 1, 2, 3, 4 diodes, when +ve cycle of ac is appeared across diode 1, then it will conduct and diode 2 will block full ac current then how will the diode 3 will get +ve cycle to conduct because full ac current is blocked by diode 2 which is connected in between diode 3 and diode 1 ?

Priyanka said:   1 decade ago
As diodes are in series current flowing through them will equal to load current.

Shreedhar said:   1 decade ago
First 2 diodes area connected in series and another 2 are also. But these 2 groups are connected in parallel. And the values of these diodes are selected such that the circuit should be balanced. Therefore load current is equal.

Ajay said:   1 decade ago
Those are connected in series thats why the same resistance available in all diodes.

Ashraful islam said:   10 years ago
When d1 and d3 forward bias, this time full current flow between this diode and reverse bias this time full current flow between d2 and d4.

Abhinav said:   9 years ago
Someone please explain.

Half the time current is flowing from one set of 2 diodes and the other two for the next half. So basically the current is available only for half time period for any diode. While current is available for whole time at load. In this manner isn't each diode carrying half of load DC current?

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