Electronics - Capacitors - Discussion
Discussion Forum : Capacitors - True or False (Q.No. 7)
7.
Between any two time constants, the charge on a capacitor changes about 63%.
Discussion:
4 comments Page 1 of 1.
Imran said:
1 decade ago
Capacitor fully charged after 5RC how can we say that it would charge up to 63% right after 2RC.
100/5=20% approximately.
100/5=20% approximately.
Durga Prasad said:
4 years ago
I think it should be false.
Bruhmagupta said:
4 years ago
From Vc=E(1-e^-t/TC).
Where :
Vc = Voltage in the capacitor,
E =Supply Voltage,
t=time,
TC=time constant = RC.
The difference between any two-time constants, say 3TC-2TC = 1TC.
Vc=E(1-e^(-TC/TC)) = E(1-e^-1),
Vc = 0.6321E,
Therefore between any two consecutive time constants, the capacitor charges up to 63%of the voltage from the supply.
Where :
Vc = Voltage in the capacitor,
E =Supply Voltage,
t=time,
TC=time constant = RC.
The difference between any two-time constants, say 3TC-2TC = 1TC.
Vc=E(1-e^(-TC/TC)) = E(1-e^-1),
Vc = 0.6321E,
Therefore between any two consecutive time constants, the capacitor charges up to 63%of the voltage from the supply.
Byle breath said:
2 years ago
A capacitor will charge to 63% on the first time constant, 86% on the second, 95% on the third, 98% on the fourth, and 99% on the fifth time constant.
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