Electronics - Capacitors - Discussion
Discussion Forum : Capacitors - General Questions (Q.No. 4)
4.
What is the reactive power in the given circuit?
0 VAR
691 
VAR
VAR44.23 mVAR
1.45 kVAR
Discussion:
36 comments Page 3 of 4.
Veer said:
1 decade ago
Find out
Xc=1/2*3.142*f*c
then
P=V^2/Xc
Xc=1/2*3.142*f*c
then
P=V^2/Xc
Shilpa said:
1 decade ago
Not so clear...
Gunda said:
1 decade ago
Ya the above example is not that clear.
Deepika said:
1 decade ago
What is ment by reactive power? and also explaine the above problem.
Nagashree said:
1 decade ago
Reactive power is the amount power that is sent back to the source from load.
Rajasree said:
1 decade ago
We know that,
p=v^2/R
Here R is the reactance of capacitor which denoted by Xc
Xc=1/(2*pi*f*c)
Xc=1446.8631 ohm
P=V^2/Xc
P=64/1446.8631
P=44.233 mw
p=v^2/R
Here R is the reactance of capacitor which denoted by Xc
Xc=1/(2*pi*f*c)
Xc=1446.8631 ohm
P=V^2/Xc
P=64/1446.8631
P=44.233 mw
Niin mukesh said:
1 decade ago
p=v^2/R
and we know,
Xc=1/(2*pi*f*c)
Xc=1446.8631 ohm
P=V^2/Xc
P=64/1446.8631
P=44.233 mw
and we know,
Xc=1/(2*pi*f*c)
Xc=1446.8631 ohm
P=V^2/Xc
P=64/1446.8631
P=44.233 mw
Lalit prasad said:
1 decade ago
How the problem can be solved?
Divz said:
1 decade ago
v^2 - v to the power 2
pi- const
f= freq of power source
pi- const
f= freq of power source
T.b.tandel said:
1 decade ago
But here given voltage r.m.s value.
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