Electronics - Capacitors - Discussion
Discussion Forum : Capacitors - General Questions (Q.No. 4)
4.
What is the reactive power in the given circuit?
0 VAR
691 
VAR
VAR44.23 mVAR
1.45 kVAR
Discussion:
36 comments Page 2 of 4.
Savi said:
1 decade ago
I didn't understand please tell me easy way.
Harika said:
10 years ago
Please can anyone explain the derivation of P=V^2/Xc?
ADARSH said:
10 years ago
Yes as we know that:
P = v^2/R.
Where R is Reactant denoted by Xc.
Xc = 1/2*pi*f**c.
Where pi-constant, f-frequency & c-capacitance.
P = v^2/R.
Where R is Reactant denoted by Xc.
Xc = 1/2*pi*f**c.
Where pi-constant, f-frequency & c-capacitance.
Yashu said:
9 years ago
What is the value of Pi?
Chandra said:
9 years ago
@Yashu.
22/7 = 3.142.
22/7 = 3.142.
Md asif said:
9 years ago
P = vi.
P = v^2/R.
Where r = capacitive load .
Xc = 1/2 * pi * f * c.
Xc = 1446.86 ohm.
P = 64/1446.86.
P = 44.21mw.
P = v^2/R.
Where r = capacitive load .
Xc = 1/2 * pi * f * c.
Xc = 1446.86 ohm.
P = 64/1446.86.
P = 44.21mw.
Kiran V said:
9 years ago
Xc = 1/2 * π * f * c.
Xc = 144.75 ohm.
P = 64/144.75.
P = 0.4421 Var.
Xc = 144.75 ohm.
P = 64/144.75.
P = 0.4421 Var.
Asha said:
8 years ago
Here RMS value is given and everyone is taking it directly. Why we are not converting it into max value?
Sindhu said:
1 decade ago
v^ and pi and f means am not understand
Ananya said:
1 decade ago
How it can be done?
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