Electronics - Capacitors - Discussion
Discussion Forum : Capacitors - General Questions (Q.No. 70)
70.
What is the impedance of an ac RC parallel circuit if the resistance is 12 ohms and the capacitive reactance equals 5 ohms?
Discussion:
24 comments Page 1 of 3.
Meow said:
6 years ago
In parallel RC/RLC/RL Ckts, get the admittance (Y) first. Y= G + jBc - jBL;
G =1/R; Bc =2pi*f*C; BL= 1/(2pi*f*L);
Y= 1/Z >>> Z is impedance.
Y = 1/12 + j1/5 >>> Z=1/Y=4.61 angle -67.38.
G =1/R; Bc =2pi*f*C; BL= 1/(2pi*f*L);
Y= 1/Z >>> Z is impedance.
Y = 1/12 + j1/5 >>> Z=1/Y=4.61 angle -67.38.
Lingamurthy said:
6 years ago
12*5/12+5.
= 60/17,
= 20/5.2.
= 4.2 ohms.
= 60/17,
= 20/5.2.
= 4.2 ohms.
Almansur said:
6 years ago
For parallel circuit finding the total impedance is you need to find 1st the total admittance Y.
Y = R+jXc.
Y = 13 ohms,
Z = 1/Y,
Z = 0.076 ohms.
Y = R+jXc.
Y = 13 ohms,
Z = 1/Y,
Z = 0.076 ohms.
Naseema said:
8 years ago
For "SERIES" RC circuit Z=√(R^2+Xc^2).
But for "PARALLEL" RC circuit Z=R*Xc/√ (R^2+Xc^2).
But for "PARALLEL" RC circuit Z=R*Xc/√ (R^2+Xc^2).
Kaveri said:
8 years ago
The correct answer is 13 ohm.
Akshar said:
8 years ago
Impedance Z in parallel RC circuit.
1/Z = √[(1/R^2)+(1/Xc)^2].
=√[(1/144)+(1/25)]=0 .21656.
Z = 1/0.21656= 4.617ohm.
1/Z = √[(1/R^2)+(1/Xc)^2].
=√[(1/144)+(1/25)]=0 .21656.
Z = 1/0.21656= 4.617ohm.
Kate said:
8 years ago
Impedance of parallel RC circuit is:
Z = R*Xc/(sqrt(R^2+Xc^2).
Plug in all values then you'll get 4.615384615 ~ 4.61
Z = R*Xc/(sqrt(R^2+Xc^2).
Plug in all values then you'll get 4.615384615 ~ 4.61
Prp said:
8 years ago
Impedance Z in parallel RC circuit.
1/Z= √[(1/R^2)+(1/Xc)^2].
=°[(1/144)+(1/25)]=0 .21656.
Z=1/0.21656= 4.617ohm.
1/Z= √[(1/R^2)+(1/Xc)^2].
=°[(1/144)+(1/25)]=0 .21656.
Z=1/0.21656= 4.617ohm.
Riyu said:
8 years ago
I also agree that the answer is 13 ohm.
Apeksha said:
9 years ago
It's 4.615.
RXC/√xc^2+r^2.
You will get 4.615.
RXC/√xc^2+r^2.
You will get 4.615.
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