Electronics - Capacitors - Discussion
Discussion Forum : Capacitors - General Questions (Q.No. 73)
73.
What is the power factor if the apparent power of a circuit is 5 W, while the true power is 4 W?
Discussion:
9 comments Page 1 of 1.
Anil patel said:
1 decade ago
cos theta=true power/apparent power
Kiran shettar said:
1 decade ago
Power factor= real power/apparent power.
Prakash said:
1 decade ago
What is meant by apparent power?
Mukesh said:
1 decade ago
Apparent power is total power,means true power + reactive power.
apparent power^2= (true power^2+ reactive power^2).
apparent power^2= (true power^2+ reactive power^2).
Gomathi said:
10 years ago
Power factor = True power/Apparent power.
= 4/5 = 0.8.
= 4/5 = 0.8.
Suresh said:
9 years ago
Real power (true power) =V * I * COS.
Apparent power = V * I.
Power factor = real power/apparent power.
So, power factor = 4/5,
= 0.8.
Apparent power = V * I.
Power factor = real power/apparent power.
So, power factor = 4/5,
= 0.8.
John said:
7 years ago
W (watts) as units.
Jadesh said:
6 years ago
Power factor has no units.
Mark J said:
1 year ago
You are correct @Jadesh.
The Power factor has no units.
The Power factor has no units.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers