Electronics - Capacitors - Discussion

Discussion Forum : Capacitors - General Questions (Q.No. 5)
5.
What is the angle theta value for a 5.6 F capacitor and a 50-ohm resistor in series with a 1.1 kHz, 5 Vac source?
27.3 degrees
62.7 degrees
–27.3 degrees
–62.7 degrees
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
16 comments Page 1 of 2.

Syed Shakeeb said:   4 years ago
@Kiran

Don't divide (XC/R) and calculate phase angle.

Calculate directly using (θ) = tan-1 (-XC / R).
You will get (θ) = -27.32˚.

KIRAN V said:   5 years ago
Given: f = 1.1 kHz; VAC = 5V; R = 50Ω ; C = 5.6μ F.

XC = 1/ (2 * π * F * C).
XC = 1 / (2 * 3.14 * 1.1 * 103 * 5.6 * 10-6)
XC = 1 / 38.6848 * 10-3,
XC = 0.02584 * 10-3,
XC = 25.84.

The phase angle between the current and voltage is calculated from the impedance triangle above as:

For RC Circuit; tan (θ) = XC / R,
(θ) = tan-1 (XC / R),
(θ) = tan-1 (25.84/50),
(θ) = tan-1 (0.5168).

(θ) = 30.02˚.

Sandy said:   8 years ago
Please explain in detail.

Abulkalam Ajath said:   10 years ago
There is no chance to calculate without a calculator.

Chandru said:   10 years ago
How to calculate this without a calculator?
(1)

Ravi said:   1 decade ago
Z = R+jX, so tanθ = X/R X = 1/2PIfc place the given values in following equation.

Vinayak birje said:   1 decade ago
Theata = tan-1(1/wrc).
So Ans = 27.3 degree.

Sign is +ve because:
Current leads the voltage by 90 degree.

Israr bagoro said:   1 decade ago
In capacitor lead the voltage by 90 degree in inductor voltage lead the current by 90.

Waqar Asmat said:   1 decade ago
In capacitor : Current lead the voltage by 90.

In Inductor: Voltage leads the current by 90.

Aswathi ms said:   1 decade ago
Incase of voltage and current which one lead inductor or capacitor.


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