Discussion :: Capacitors - General Questions (Q.No.21)
|M.V.Krishna said: (Sep 3, 2011)|
|Rita said: (Sep 12, 2011)|
|What about capacitive reactance? Total impedance is required which also include Xc.|
|Ravi Jumwal said: (Oct 4, 2011)|
|This is the total current flowing through the circuit so where the matter of Xc come from.|
|Sobia said: (Apr 16, 2012)|
|Reactance if we calculate Xc=1/(2*pi*f*c) is 99.47 which is very low as compared to R which is 1k by above formula explained by Krishna so we ignore 99.91 and call total resistance 1k|
|Divik said: (May 19, 2012)|
|The solution of question also states that with such alternating high frequency the capacitive reactance becomes negligible as it also the fundamental property of capacitor.|
|Qummar said: (Aug 1, 2012)|
|We get Xc = 99.47 and R = 1k and we know that total impedance is sqrt (R*R+Xc*Xc) = 1.004k.|
|Mukesh said: (Nov 13, 2012)|
(Vt)^2=I^2[R^2 + Xc^2];
(40)^2=(40*10^-3)^2[R^2 + (99.47)^2];
|Arun said: (Oct 24, 2013)|
|Xc = 99.52 OHM.
Vc = I*Xc = 3.98 V.
Vr = SQRT (Vs^2-Vc^2) = 39.8 V.
Z= SQRT (R^2+ Xc^2) = 999.99 OHM ~ 1 KILO OHM.
|Al Ongsuco said: (Nov 11, 2014)|
|How did you get the frequency?|
|Shubham said: (Jan 30, 2015)|
|What is total circuit impedance?|
|Ameya Pagare said: (Jul 18, 2019)|
|The value of XC is given by the passive HPF formula for Xc.
Xc= 99.52 ohm.
|Kiran V said: (Sep 19, 2020)|
|Given: I = 40 m A; C = 0.4μF; f = 4 kHz; V = 40 Vac; ZT =?
Z = Vac /I.
Z = 40 / 40 m A = 1 * 10^3.
Z = 1 k Ω.
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