Electronics - Capacitors - Discussion

Discussion Forum : Capacitors - General Questions (Q.No. 19)
19.
With a 500 kHz signal source, what would be the value of a capacitor yielding a capacitive reactance of 1 k omega.gif?
318 pF
2 nF
3.18 F
2 F
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
10 comments Page 1 of 1.

Syed Shakeeb S said:   4 years ago
Yielding means giving way under pressure.

KIRAN V said:   5 years ago
Given: f = 500 kHz; XC = 1 kΩ; C =?

XC = 1 / (2 * π * f * C).
C = 1 / (2 * π * f * XC).
C = 1 / (2 * 3.14 * 500 * 10^3 * 1 * 10&3) .
C = 1 / 3140 * 10^6.
C = 3.18 * 10^-4 * 10^-6.
C = 3.18 * 10^-10 or 318 * 10^-12.
And we get;
C = 3.18 p F.

Aadi said:   7 years ago
@Hemanth.

Please explain to me, how you converted the value of micro to pico?

Hemanth R said:   7 years ago
C=1/2*π*f*Xc.

C=1/2*3.14*500*10^3*1*10^3.
C=1/3140*10^6,
C=1*10^-6/3140,
C=0.318*10^-3*10^-6,
C=0.318*10^-9F or 318*10^-12F,
Therefore C=318pF.

KIRAN V said:   9 years ago
Formula:
Xc = 1/(2Pi * f * c).
Xc = 1k ohm.
f = 500 kHz.

Hence,
c = 31.8 pF.

Ajinkya said:   9 years ago
You are right @Ritika. My answer is also C.

Ritika said:   9 years ago
Formula:
Xc = 1/(2Pi * f * c).

Xc = 1k ohm.
f = 500 kHz.

So, c = 1/(2 * 3.14 * 500K * 1k).
1/(3140 * 10^6).
3.18 micro F.

Sandeep kumar said:   1 decade ago
Formula:

Xc=1/(2Pi*f*c).

Xc=1k ohm.
f=500 kHz.

Hence
c=318 pF Answer.

Sri said:   1 decade ago
Here f and r values given by using this two calculate the c means f =1/2pi rc formulae.

Seshendra said:   1 decade ago
We know capacitive reactance Xc = 1/(2*pi*f*c)... In this we know Xc,f find out the c...

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