Electronics - Capacitors - Discussion

6. 

When a 4.7 F capacitor is connected to a 1 kHz source, what is its capacitive reactance?

[A]. 4.7 ohms
[B]. 29.5 ohms
[C]. 34 ohms
[D]. 213 ohms

Answer: Option C

Explanation:

No answer description available for this question.

Seshendra said: (Nov 17, 2010)  
Capacitive reactance= 1/(2*pi*f*c).

Avi said: (Aug 27, 2011)  
Any one explain this question.

Ravi said: (Sep 21, 2011)  
Xc=1/Jwc
=1/2*pi*f*c

Keeping factor aside. As we interested mainly on reactance .

So substituting in above relation.. We will get

1/2*3.12*1k*4.7micro =34 ohm

Ravi said: (Sep 21, 2011)  
Xc=1/Jwc
=1/2*pi*f*c

Keeping factor aside. As we interested mainly on reactance .

So substituting in above relation.. We will get

1/2*3.12*1k*4.7micro =34 ohm

Muhammad Jamal said: (Feb 15, 2012)  
Xc=jwc
as w=2*pi*f*c
Keeping factor aside
Xc=1/2*pi*f*c
by putting the values we have
=1/2*3.14*1000*4.7u
=34 ohms

Blessy Mathew said: (Aug 31, 2012)  
Xc=1/Jwc
=1/2*pi*f*c

Narendra said: (May 29, 2014)  
What calculated pi value?

Kevin Ochieng said: (Nov 4, 2014)  
How is 34 coming?

Prashanth Kotian said: (Jan 30, 2015)  
= 1/2x3.14x1000x4.7x10-6.
= 1/2x3.14x1x4.7x10-3.
= 1000/2x3.14x1x4.7.
= 1000/29.516.
= 34 ohms.

Dan said: (Apr 27, 2016)  
@Prashanth Kotian.

How 4.7 x 10-6 becomes 4.7 x 10-3?

Mahesh said: (May 26, 2016)  
Xc = 1/(2 * 3.14 * f * c).
= 1/(2 * 3.14 * 1000 * 0.0000047).
= 33.86.

Sk Sajahan said: (Nov 5, 2016)  
= 1/2 x 3.14 x 1000x4.7 x 10-6.
= 1/2 x 3.14 x 1 x 4.7 1 0-3.
= 1000/2 x 3.14 x 1 x 4.7.
= 1000/29.516.
= 34 ohms.

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