### Discussion :: Capacitors - General Questions (Q.No.6)

Seshendra said: (Nov 17, 2010) | |

Capacitive reactance= 1/(2*pi*f*c). |

Avi said: (Aug 27, 2011) | |

Any one explain this question. |

Ravi said: (Sep 21, 2011) | |

Xc=1/Jwc =1/2*pi*f*c Keeping factor aside. As we interested mainly on reactance . So substituting in above relation.. We will get 1/2*3.12*1k*4.7micro =34 ohm |

Ravi said: (Sep 21, 2011) | |

Xc=1/Jwc =1/2*pi*f*c Keeping factor aside. As we interested mainly on reactance . So substituting in above relation.. We will get 1/2*3.12*1k*4.7micro =34 ohm |

Muhammad Jamal said: (Feb 15, 2012) | |

Xc=jwc as w=2*pi*f*c Keeping factor aside Xc=1/2*pi*f*c by putting the values we have =1/2*3.14*1000*4.7u =34 ohms |

Blessy Mathew said: (Aug 31, 2012) | |

Xc=1/Jwc =1/2*pi*f*c |

Narendra said: (May 29, 2014) | |

What calculated pi value? |

Kevin Ochieng said: (Nov 4, 2014) | |

How is 34 coming? |

Prashanth Kotian said: (Jan 30, 2015) | |

= 1/2x3.14x1000x4.7x10-6. = 1/2x3.14x1x4.7x10-3. = 1000/2x3.14x1x4.7. = 1000/29.516. = 34 ohms. |

Dan said: (Apr 27, 2016) | |

@Prashanth Kotian. How 4.7 x 10-6 becomes 4.7 x 10-3? |

Mahesh said: (May 26, 2016) | |

Xc = 1/(2 * 3.14 * f * c). = 1/(2 * 3.14 * 1000 * 0.0000047). = 33.86. |

Sk Sajahan said: (Nov 5, 2016) | |

= 1/2 x 3.14 x 1000x4.7 x 10-6. = 1/2 x 3.14 x 1 x 4.7 1 0-3. = 1000/2 x 3.14 x 1 x 4.7. = 1000/29.516. = 34 ohms. |

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