Electronics - Capacitors - Discussion
Discussion Forum : Capacitors - General Questions (Q.No. 51)
51.
What is the circuit's impedance?
1192 
843
723
511
Discussion:
5 comments Page 1 of 1.
Sumit aole said:
1 decade ago
v=10;
total current I =sqrt(Ic^2+Ir^2);
I = sqrt(7.076*10*^-3^2+ 4.608*10*^-3^2);
I= 8.444*10^-3
z = 10/8.444*10^-3= 1184.25~~1192;
total current I =sqrt(Ic^2+Ir^2);
I = sqrt(7.076*10*^-3^2+ 4.608*10*^-3^2);
I= 8.444*10^-3
z = 10/8.444*10^-3= 1184.25~~1192;
(1)
Sumeet said:
9 years ago
Total current = square root(Ic^2 + Ir^2).
Z = Voltage/total current = 10/total current.
Z = Voltage/total current = 10/total current.
Sivapramod said:
1 decade ago
No. This is a parallel RC Circuit, So use the below formula,
Z = RXc/sqrt(R^2+Xc^2).
Z = RXc/sqrt(R^2+Xc^2).
Yogita lakhi said:
1 decade ago
If we solve it using Z=sqrt (R^2+Xc^2), the answer is different.
(1)
Lana said:
10 years ago
Can anyone please show the correct solution for this? Thank you!
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