Electronics - Capacitors - Discussion

14. 

What is the circuit's total current?

[A]. 4.57 mA
[B]. 9.327 mA
[C]. 11.570 mA
[D]. 13.830 mA

Answer: Option A

Explanation:

No answer description available for this question.

Vasu said: (Sep 24, 2011)  
I= sq root (Ir^2+Ic^2)
so I= sq root (0.785^2 + 4.508^2)
=4.57mA

Zohra said: (Nov 5, 2011)  
Not clear.

Devadas said: (Feb 10, 2012)  
I=0+Ir+(11+(-11)+(0+Ic))
where 11 is a number

You can take any number in that place.

Ashutosh said: (Aug 25, 2012)  
Current across the capctor leads the current across the resistor by 90 in phase diagram.

so,total current=sqrt(sq(Icapactor)+sq(Iresistor)).

Ravi said: (Jan 2, 2015)  
We know that V=IZ where z=R//X where X=1/2PIfc.

Anee said: (Jul 2, 2015)  
Current in parallel form added.

Rishitha Chittoory said: (May 18, 2016)  
Why square rooting the value?

Hirak said: (Jul 11, 2017)  
Why square rooting Ir & Ic?

Jjc said: (Jul 29, 2017)  
Ir and Ic are not in phase (90 degrees out of phase).

In a graphical analysis, they will form a right triangle, the longest side (hypotenuse) is the total current (geometric sum), which can be solved by using the Pythagorean theorem. It=sqrt(Ir^2 + Ic^2).

Post your comments here:

Name *:

Email   : (optional)

» Your comments will be displayed only after manual approval.