Electronics - Capacitors - Discussion

53. 

What is the impedance of this circuit?

[A]. 5928
[B]. 2000
[C]. 1902
[D]. 1798

Answer: Option A

Explanation:

Impedance Cannot be Directly Measured, We Need to find Xc first.

So,

Xc = 1/2πfC.

Xc = 1/( 2 x 3.14 x 5000 x 0.01 x 10-6 ).

Xc = 3184.7.

Z = Sqrt( Xc2 + R2 ).

Z = Sqrt( 3184.72 + 50002 ).

Z = 5928 Ω.


Vignesh said: (Sep 8, 2013)  
Frequency = 1KHz in schematic diagram, but it has been substituted as 5KHz while solving. How?

Ankur Tyagi said: (Nov 24, 2013)  
X= Sqrt(R^2+ Xc^2).

It Must be more than 5 Kohm.

Post your comments here:

Name *:

Email   : (optional)

» Your comments will be displayed only after manual approval.