Electronics - Capacitors - Discussion
Discussion Forum : Capacitors - General Questions (Q.No. 53)
53.
What is the impedance of this circuit?
5928 
2000
1902
1798
Answer: Option
Explanation:
Impedance Cannot be Directly Measured, We Need to find Xc first.
So,
Xc = 1/2πfC.
Xc = 1/( 2 x 3.14 x 5000 x 0.01 x 10-6 ).
Xc = 3184.7.
Z = Sqrt( Xc2 + R2 ).
Z = Sqrt( 3184.72 + 50002 ).
Z = 5928 Ω.
Discussion:
2 comments Page 1 of 1.
Ankur Tyagi said:
1 decade ago
X= Sqrt(R^2+ Xc^2).
It Must be more than 5 Kohm.
It Must be more than 5 Kohm.
Vignesh said:
1 decade ago
Frequency = 1KHz in schematic diagram, but it has been substituted as 5KHz while solving. How?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers