Electronics - Capacitors - Discussion
Discussion Forum : Capacitors - General Questions (Q.No. 41)
41.
What is the voltage across a capacitor after being charged from a 100 V source for a period of one time constant?
Discussion:
5 comments Page 1 of 1.
SANA AFREEN said:
1 decade ago
VOLTAGE ACROSS A CAPACITOR FOR ONE TIME CONSTT. WILL BE 0.63 TIMES OF SUPPLY VTG. S0 63 VOLT.ITS ACCORDING TO THE CAPACITOR CHARGING GRAPH.
Elek kick said:
1 decade ago
vc = vin ( 1 - e^(-t/RC))
For one time constant t = RC
Therefore....
vc = vin ( 1 - e^(-t/t))
vc = vin ( 1 - e^-1)
e^1 = 2.718..... e^-1 = 1/2.718
vc = vin ( 1 - (1/2.718))
vc = vin ( (2.718 - 1) / 2.718 )
vc = vin ( 1.718 / 2.718 )
vin = 100V
vc = 100V (0.632)
vc = 63.2V or 63V
For one time constant t = RC
Therefore....
vc = vin ( 1 - e^(-t/t))
vc = vin ( 1 - e^-1)
e^1 = 2.718..... e^-1 = 1/2.718
vc = vin ( 1 - (1/2.718))
vc = vin ( (2.718 - 1) / 2.718 )
vc = vin ( 1.718 / 2.718 )
vin = 100V
vc = 100V (0.632)
vc = 63.2V or 63V
(1)
Paul said:
7 years ago
I am not getting, please explain in detail to get it clearly.
(1)
Ameya said:
6 years ago
One time constant is equal to 0.63.
So for 100 volts,
=100*0.63,
=63.
So for 100 volts,
=100*0.63,
=63.
Rashmi said:
6 years ago
@Ameya nice explanation, short formulas always helps:).
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