Electronics - Capacitors - Discussion
Discussion Forum : Capacitors - General Questions (Q.No. 31)
31.
If C1, a 4.7 
F capacitor, and C2, a 3.3 F capacitor are in series with 18 Vdc applied, what is the voltage across C1?
F capacitor, and C2, a 3.3 F capacitor are in series with 18 Vdc applied, what is the voltage across C1?Discussion:
17 comments Page 1 of 2.
Kiran said:
1 decade ago
A transient current flows to charge the capacitor. When it gets charged then this capacitor acts as a break in the circuit. Or we can say that ist capacitor acts as DC supply for next capacitor. So same happens for next one.
M.V.KRISHNA said:
1 decade ago
Given
C1=4.7uF, C2=3.3uF, V=18dc;
two capacitors are in series so
Cs=c1*c2/(c1+c2);
Cs=4.7uF * 3.3uF/(4.7uF + 3.3uF);
Cs=1.93uF;
voltage across V1= VCs/C1;
=> 18*1.93/4.7
=7.4V
C1=4.7uF, C2=3.3uF, V=18dc;
two capacitors are in series so
Cs=c1*c2/(c1+c2);
Cs=4.7uF * 3.3uF/(4.7uF + 3.3uF);
Cs=1.93uF;
voltage across V1= VCs/C1;
=> 18*1.93/4.7
=7.4V
Pankaj garg said:
1 decade ago
Total Capacitance Ct = c1*c2/c1+c2 =
C=g/V
We find out the charge
q=Ct*V
THEN WE Find out the voltage across C1
V1= q/c1
C=g/V
We find out the charge
q=Ct*V
THEN WE Find out the voltage across C1
V1= q/c1
Ahsan Ali said:
8 years ago
C1(v) =total voltage * c2/c1 + c2.
=18*3.3/4.7+3.3.
=59.4/8.0.
=7.425.
=18*3.3/4.7+3.3.
=59.4/8.0.
=7.425.
Balgopal said:
8 years ago
Cv1=Vt*Cv2/(Cv1+Cv2).
Cv1=4.7uF,
Cv2=3.3uF,
Vt=18v,
Cv1=18v*3.3/(4.7+3.3)uF,
Cv1=7.4v.
Cv1=4.7uF,
Cv2=3.3uF,
Vt=18v,
Cv1=18v*3.3/(4.7+3.3)uF,
Cv1=7.4v.
Yamini said:
1 decade ago
Capacitor acts as open circuit for dc current because frequency f=0 in dc current.
Ashish Kumar said:
7 years ago
Voltage across C1 by voltage division rule.
Vc1= Vac*(C2/(C1+C2)),
= 7.4V.
Vc1= Vac*(C2/(C1+C2)),
= 7.4V.
(1)
Muhammad fayyaz said:
1 decade ago
The combined capacitance Cs = [c1c2/ {c1+c2}]
V1 = V0Cs / C1 and V2 = V0Cs /C2.
V1 = V0Cs / C1 and V2 = V0Cs /C2.
Dani said:
4 years ago
How about the energy it consumed, what is the answer? Please explain in detail.
Mahadev said:
1 decade ago
All 18 Vdc should be across c1 because for dc capacitor will be open circuit.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers