Electronics - Capacitors - Discussion
Discussion Forum : Capacitors - General Questions (Q.No. 7)
7.
What is the total capacitance?
Discussion:
10 comments Page 1 of 1.
Vijaya veenam said:
1 decade ago
If the capacitors are in series then total capacitance is
(1/c)=(1/c1)+(1/c2)+(1/c3)+.....
If the capacitors are in parallel then total capacitance is
c=c1+c2+c3+......
If the resistors are in series then total resistance is
R=R1+R2+R3+.....
If the resistors are in PARALLEL then total resistance is
(1/R)=(1/R1)+(1/R2)+(1/R3)+.....
(1/c)=(1/c1)+(1/c2)+(1/c3)+.....
If the capacitors are in parallel then total capacitance is
c=c1+c2+c3+......
If the resistors are in series then total resistance is
R=R1+R2+R3+.....
If the resistors are in PARALLEL then total resistance is
(1/R)=(1/R1)+(1/R2)+(1/R3)+.....
(1)
NARENDRA said:
1 decade ago
When the capacitors are in parallel then the capacintance =c1+c2+c3
Therefore, capacitance =1 + 3 + 8 = 12 F
Therefore, capacitance =1 + 3 + 8 = 12 F
M.V.KRISHNA said:
1 decade ago
When capacitors are in parallel:.
C = c1+c2+c3+...
C = c1+c2+c3+...
Vpc said:
1 decade ago
If all the positive ends are connected to one end and all the negative ends are connected to one end then the connection is said to be parallel connection and if the positive end of first capacitor is connected to the negative end of second and positive of second to negative of third and so on and the positive end of last connected to negative end of first then the capacitors are said to be in series.
Kishan TJ said:
1 decade ago
When the capacitors are in parallel then the capacintance =c1+c2+c3
Therefore, capacitance =1 + 3 + 8 = 12 F
Therefore, capacitance =1 + 3 + 8 = 12 F
Arzoo said:
1 decade ago
When capacitors are said to be connected in parallel then the total capacitance can be measured by adding them, i.e.,
c1+c2+c3=1+3+8=12F.
c1+c2+c3=1+3+8=12F.
Ankur Pandey said:
1 decade ago
If all the +ve ends are connected to one and all the -ve ends are connected to one end, the connection is said to be Parallel connection. So This question can solve by this way
C=C1+C2+C3.
Thus, 1+3+8=12F.
C=C1+C2+C3.
Thus, 1+3+8=12F.
Gopal shukla said:
9 years ago
c1 + c2 + c3 = 1 + 3 + 8 = 12.
Rakshana said:
8 years ago
I agree @Kishan Tj.
MOHIT J MISTRY said:
5 years ago
The Total Capacitance In Parallel.
CT = C1 + C2 + C3.
CT = 1 + 3 + 8,
CT = 12.
CT = C1 + C2 + C3.
CT = 1 + 3 + 8,
CT = 12.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers