Electronics - Capacitors - Discussion
Discussion Forum : Capacitors - General Questions (Q.No. 71)
71.
What will a 1 
F capacitor store?
F capacitor store?one coulomb of charge
6.24 x 1012 electrons
one volt
one A of current
A of currentDiscussion:
4 comments Page 1 of 1.
Kiran shettar said:
1 decade ago
1 Farad = 1 Coulomb / 1 Volt.
1 Coulomb = 6.24x10^18.
Now,
1mF = 6.24*10^12 electrons/volt.
1 Coulomb = 6.24x10^18.
Now,
1mF = 6.24*10^12 electrons/volt.
Ashok said:
1 decade ago
One electron charge = 1.6*10^-19 coulombs, So one coulomb = 1/1.6*10^-19 electrons = 6.25*10^18 electrons.
We know that q = c*v.
One farad = one coulomb/one volt = one coluomb = 6.25*10^18 electrons.
1 microfarad = 6.25*10^18 *10^-6 = 6.24*10^12 electrons.
We know that q = c*v.
One farad = one coulomb/one volt = one coluomb = 6.25*10^18 electrons.
1 microfarad = 6.25*10^18 *10^-6 = 6.24*10^12 electrons.
Vishal said:
10 years ago
I am not getting answer can you explain briefly?
Neeen said:
8 years ago
Thanks, @Ashok & @Kiran.
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