Electronics - Bipolar Junction Transistors (BJT) - Discussion
Discussion Forum : Bipolar Junction Transistors (BJT) - General Questions (Q.No. 21)
21.
If a 2 mV signal produces a 2 V output, what is the voltage gain?
Discussion:
5 comments Page 1 of 1.
Raj said:
10 years ago
Voltage gain = Output/Input.
= 2v/0.002 v (2/1000) because IP is mv.
= 1000 v.
= 2v/0.002 v (2/1000) because IP is mv.
= 1000 v.
(1)
Sachin said:
1 decade ago
Voltage Gain = OUTPUT Voltage/INPUT Voltage.
Av = 2/2*10^-3.
= 2*10^3 / 2.
Av = 1000v.
Av = 2/2*10^-3.
= 2*10^3 / 2.
Av = 1000v.
(1)
SIMSON M said:
1 decade ago
Voltage Gain = OPV/IPV.
So,
Av = 2/2*10^-3.
= 2*10^3 / 2.
Av = 1000v.
So,
Av = 2/2*10^-3.
= 2*10^3 / 2.
Av = 1000v.
(1)
Debalaxmi rout said:
1 decade ago
Av=2v/2mv
=2/2*10^-3
=10^3
=1000
=2/2*10^-3
=10^3
=1000
(1)
Girish said:
1 decade ago
voltage gain=output voltage/input voltage
so voltage gain=2v/2mv
=2/2 x10^-3
=1000v
so voltage gain=2v/2mv
=2/2 x10^-3
=1000v
(1)
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