Electronics - Bipolar Junction Transistors (BJT) - Discussion
Discussion Forum : Bipolar Junction Transistors (BJT) - General Questions (Q.No. 31)
31.
What is the collector current for a C-E configuration with a beta of 100 and a base current of 30 
A?
A?30 A
A.3 A
A3 mA
3 MA
Discussion:
10 comments Page 1 of 1.
Ruchi said:
6 years ago
Please explain the answer clearly.
Pooja waghmare said:
6 years ago
In CE configuration, if beta = 100, leakage current ICEO = 150 microA. If the base current is 0.2 mA, Calculate the value of IC, IE and alpha.
Kittu said:
1 decade ago
Beta : Ic/Ib.
Ic : ib*beta.
Ic : 100*30.
: 3000uA.
: 3mA.
Ic : ib*beta.
Ic : 100*30.
: 3000uA.
: 3mA.
Madhusudan Kumar said:
1 decade ago
Beta=Ic/Ib.
And Ib=30micro ampere
Therefore,
Ic=beta*Ib
Ic=100*30*10^(-6)A
Ic=3mA.
And Ib=30micro ampere
Therefore,
Ic=beta*Ib
Ic=100*30*10^(-6)A
Ic=3mA.
Vishnu said:
1 decade ago
Ic=beta*Ib
Monisha said:
1 decade ago
ic=beta*ib
Deepak said:
1 decade ago
ib= .000030
beta= 100
then ic= .030
or 30UA
beta= 100
then ic= .030
or 30UA
Zohra jabeen said:
1 decade ago
Beta ratio=Ic/Ib
=> Ic=beta*Ib
=> Ic=100*30=3000
=> 3000/1000=3mA
=> Ic=beta*Ib
=> Ic=100*30=3000
=> 3000/1000=3mA
Saquib Khan said:
1 decade ago
beta=Ic/Ib
Deepa said:
1 decade ago
Ic=beta*Ib
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