Electronics - Bipolar Junction Transistors (BJT) - Discussion

Discussion Forum : Bipolar Junction Transistors (BJT) - General Questions (Q.No. 25)
25.
Total emitter current is:
IE – IC
IC + IE
IB + IC
IB – IC
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
3 comments Page 1 of 1.

Arenasi said:   7 years ago
Ie = Ic + Ib.

Ammu said:   1 decade ago
Is the answer same in both the cases? i.e in both NPN And PNP ?

Girish said:   1 decade ago
emitter current=collector current+base current

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