Electronics - Bipolar Junction Transistors (BJT) - Discussion
Discussion Forum : Bipolar Junction Transistors (BJT) - General Questions (Q.No. 3)
3.
A transistor has a 
of 250 and a base current, IB, of 20 
A. The collector current, IC, equals:
of 250 and a base current, IB, of 20 A. The collector current, IC, equals:500 A
A5 mA
50 mA
5 A
Discussion:
17 comments Page 2 of 2.
Laxman said:
1 decade ago
Ic=Beta*Ib
Ic=250*20/1000000
=5000/1000000
Ic=5mA
Ic=250*20/1000000
=5000/1000000
Ic=5mA
Rajnish Tiwari said:
1 decade ago
Beta=Ic/Ib
Ic=Beta*Ib
Ic=250*20/1000000
Ic=5mA
Ic=Beta*Ib
Ic=250*20/1000000
Ic=5mA
Shreshthagupta said:
1 decade ago
Ic=Beta*Ib
=250*20*10^-6
=5*10^-6
=5mA
=250*20*10^-6
=5*10^-6
=5mA
Tejaswini said:
1 decade ago
Ic = BIb.
Ic = 250*20*10^-6.
Ic = 5mA.
Ic = 250*20*10^-6.
Ic = 5mA.
Koudinya said:
1 decade ago
Ic = Beta x Ib
Jyothi said:
1 decade ago
Ic=BIb
=250*20*10^-6
5 mA
=250*20*10^-6
5 mA
Deepen said:
7 years ago
You are right, Agree @Kalpana.
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