Electronics - Bipolar Junction Transistors (BJT) - Discussion
Discussion Forum : Bipolar Junction Transistors (BJT) - General Questions (Q.No. 3)
3.
A transistor has a 
of 250 and a base current, IB, of 20 
A. The collector current, IC, equals:
of 250 and a base current, IB, of 20 A. The collector current, IC, equals:500 A
A5 mA
50 mA
5 A
Discussion:
17 comments Page 1 of 2.
Koudinya said:
1 decade ago
Ic = Beta x Ib
Laxman said:
1 decade ago
Ic=Beta*Ib
Ic=250*20/1000000
=5000/1000000
Ic=5mA
Ic=250*20/1000000
=5000/1000000
Ic=5mA
Rajnish Tiwari said:
1 decade ago
Beta=Ic/Ib
Ic=Beta*Ib
Ic=250*20/1000000
Ic=5mA
Ic=Beta*Ib
Ic=250*20/1000000
Ic=5mA
ARGHYA DAS said:
1 decade ago
Beta is 250,Ib=20
collector current Ic=(Ib*beta)/10^6
Ic=5000/10^6
=5mA
collector current Ic=(Ib*beta)/10^6
Ic=5000/10^6
=5mA
Sashibhusan Panda said:
1 decade ago
For dc operation of bjd
Ic=Ie+(beta)Ib
But for Ib=20ua current value, Ie negligible so considered as zero.
=> Ic=250*20uA=5mA. (ans)
Ic=Ie+(beta)Ib
But for Ib=20ua current value, Ie negligible so considered as zero.
=> Ic=250*20uA=5mA. (ans)
Micheal said:
1 decade ago
Bdc is 250 and current base Ib=20
so
they formula say that collector current(Ic)= Ib*Bdc
then IC= 20*250
=5000
sol: 5mA
so
they formula say that collector current(Ic)= Ib*Bdc
then IC= 20*250
=5000
sol: 5mA
Jyothi said:
1 decade ago
Ic=BIb
=250*20*10^-6
5 mA
=250*20*10^-6
5 mA
Shreshthagupta said:
1 decade ago
Ic=Beta*Ib
=250*20*10^-6
=5*10^-6
=5mA
=250*20*10^-6
=5*10^-6
=5mA
Bala.j said:
1 decade ago
THE FORMULA USED TO FIND OUT THE IC IS Ic = Ib*GAIN
= (20*10^-6)*(250)
=5*10^3* 10^-6
= 5mA
= (20*10^-6)*(250)
=5*10^3* 10^-6
= 5mA
KALPANA said:
1 decade ago
In common emiter configuration, amplification factor is given by BETE=Ic/Ib.
Ic=BETA*Ib
=250*(20*10^-6)
=5000*10^-6
=5mA
Ic=BETA*Ib
=250*(20*10^-6)
=5000*10^-6
=5mA
(1)
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