Electronics - Alternating Current vs Direct Current - Discussion
Discussion Forum : Alternating Current vs Direct Current - General Questions (Q.No. 22)
22.
If a voltmeter measures a sine wave as 500 mV, what would be its average value?
Answer: Option
Explanation:
Some AC Voltage Conversion:
Peak to rms: multiply peak by 0.707.
Peak to average: multiply peak by 0.637.
Rms to peak: multiply rms by 1.414.
Rms to average: multiply rms by 0.9.
Average to rms: multiply avg by 1.111.
Average to peak: multiply avg by 1.567.
Mostly voltmeter shows rms value. So, Vav = 0.9*Vrms
= 0.9*500.
= 450mV ~ [D] 451 mV.
Discussion:
6 comments Page 1 of 1.
Guest said:
1 decade ago
The Reading on voltmeter is Vpk or Vrms ?
Pavan said:
1 decade ago
Answer is 451.0 mv because voltmeter will measure rms but not average value.
So given Vrms = 500mv.
So Vp = 500mv *(1.414) = 707mv.
And finally, Vavg = Vp*(0.637) = 451.0 mv.
So given Vrms = 500mv.
So Vp = 500mv *(1.414) = 707mv.
And finally, Vavg = Vp*(0.637) = 451.0 mv.
(1)
Ajinkya said:
9 years ago
Thank you @Pavan.
Tony said:
6 years ago
Is average value of sine wave is zero?
Sajan kumar p said:
3 years ago
@Tony.
Yes, you are correct the .avg value of the sine wave is zero.
Yes, you are correct the .avg value of the sine wave is zero.
KOMAL KUMARI said:
2 years ago
Vrms = 500mv.
Vrms = Vm/√2.
500 = Vm/√2.
Vm = 707.
Vavg= 2Vm/π.
= 2×707/3.14
= 450.
Vrms = Vm/√2.
500 = Vm/√2.
Vm = 707.
Vavg= 2Vm/π.
= 2×707/3.14
= 450.
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