Electronics - Alternating Current vs Direct Current - Discussion
Discussion Forum : Alternating Current vs Direct Current - General Questions (Q.No. 19)
19.
If a sine wave signal is 100 mV peak-to-peak, how many volts would be measured by a voltmeter?
Discussion:
8 comments Page 1 of 1.
Neeraja Pamala said:
1 decade ago
Peak to peak = 2*sqrt2*RMS value.
Ron_dip2000 said:
1 decade ago
RMS value = (Peak to peak/2)/sqrt 2.
= (100/2)/1.414 = 35.4mV.
= (100/2)/1.414 = 35.4mV.
Nisha said:
1 decade ago
AC voltmeter always measure RMS value.
RMS value = (vm/sqrt (2)).
Where Vm is max. Amplitude in positive direction.
RMS value = (vm/sqrt (2)).
Where Vm is max. Amplitude in positive direction.
Sweetu rathore said:
1 decade ago
Peak value = 2*sqrt 2* rms value.
Rishabh said:
1 decade ago
Vrms = Vm/2(2)^1/2.
Shadan said:
7 years ago
100mV =2Vm.
Vm(peak) =50mV.
So RMS=Vm/root2,
50/1.414=35.4 mV.
Vm(peak) =50mV.
So RMS=Vm/root2,
50/1.414=35.4 mV.
Nallu said:
6 years ago
Agree with your answer, thanks @Sadan.
Historia said:
4 years ago
Since it is 100mV pk-to-pk it need to be divided in to half to get the Vpeak only. 100mV/2 = 50mV then voltmeter always measure the RMS of an AC voltage.
Therefore RMS value = Vp/√2 = 50mV/√2 = 35.355mV.
Therefore RMS value = Vp/√2 = 50mV/√2 = 35.355mV.
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