Electronics - Alternating Current vs Direct Current - Discussion
Discussion Forum : Alternating Current vs Direct Current - General Questions (Q.No. 12)
12.
What is the average value of a 12 V peak wave?
Discussion:
5 comments Page 1 of 1.
Nikhita said:
1 decade ago
Vavg = (2/3.14)*Vpeak.
= 0.636*Vpeak.
= 0.636*12.
= 7.632.
Therefore answer option C.
= 0.636*Vpeak.
= 0.636*12.
= 7.632.
Therefore answer option C.
Shailesh said:
1 decade ago
Volts avg=0.637 X Vp (peak).
0.637 X 12 Vp = 8.316 Vavg.
0.637 X 12 Vp = 8.316 Vavg.
Bharatiya Seva said:
1 decade ago
Vavg = 0.637 x Vmax.
Vavg = 0.637 x 12 = 7.64 V.
Vavg = 0.637 x 12 = 7.64 V.
Akhilesh prajapati said:
1 decade ago
Avg = 2Vm/3.14
= 2*12/3.14
= 7.64
= 2*12/3.14
= 7.64
Gayathri said:
1 decade ago
How you said it is apeak value?
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