Electronics - Alternating Current and Voltage - Discussion
Discussion Forum : Alternating Current and Voltage - General Questions (Q.No. 16)
16.
What is the average voltage when a rectangular wave's base line voltage is 20 V, its peak-to-peak voltage is 50 V, and its duty cycle is 20%?
Discussion:
13 comments Page 1 of 2.
Vasu said:
1 decade ago
Can anyone explain this in detail ?
Hanish said:
1 decade ago
Please anyone explain this.
Hasan said:
1 decade ago
V(av)=Vpp*.634
Ranjan said:
1 decade ago
Duty cycle=20%,
(ton/(ton+toff))=0.2, when calculated we get toff=4ton
now the waveform is confined between 20 v to 70 v as it is stated that the base line is 20v and peak to peak is 50v..
avg= (1/T)*[(70*ton+ 20*toff)], where T=ton+toff
Calculate it and u will get 30 v..hope it will help someone.
(ton/(ton+toff))=0.2, when calculated we get toff=4ton
now the waveform is confined between 20 v to 70 v as it is stated that the base line is 20v and peak to peak is 50v..
avg= (1/T)*[(70*ton+ 20*toff)], where T=ton+toff
Calculate it and u will get 30 v..hope it will help someone.
Sambhrama said:
1 decade ago
Duty Cycle=20% or
Ton/(Ton+Toff)=0.2 ----(1)
Simplyfying (1) we will get (Toff/Ton)=4
Avg=(1/T)*[(70*ton+ 20*toff)],where T=Ton+Toff
Avg=(1/Ton+Toff)*[(70*ton+ 20*toff)]
Avg=(1/Ton+Toff)* Ton [(70+ 20*(Toff/Ton))]
Avg=(Ton/Ton+Toff)* [(70+ 20*(Toff/Ton))]
Since (Ton/Ton+Toff)=Duty Cycle=0.2
Avg=(0.2)* [(70+ 20*(Toff/Ton))]
Since (Toff/Ton)=4
Avg=(0.2)* [(70+ 20*(4))]
Avg=30 volts
Ton/(Ton+Toff)=0.2 ----(1)
Simplyfying (1) we will get (Toff/Ton)=4
Avg=(1/T)*[(70*ton+ 20*toff)],where T=Ton+Toff
Avg=(1/Ton+Toff)*[(70*ton+ 20*toff)]
Avg=(1/Ton+Toff)* Ton [(70+ 20*(Toff/Ton))]
Avg=(Ton/Ton+Toff)* [(70+ 20*(Toff/Ton))]
Since (Ton/Ton+Toff)=Duty Cycle=0.2
Avg=(0.2)* [(70+ 20*(Toff/Ton))]
Since (Toff/Ton)=4
Avg=(0.2)* [(70+ 20*(4))]
Avg=30 volts
(1)
Deepak kumar joshi said:
1 decade ago
Duty cycle = 20%,
(ton/(ton+toff)) = 0.2, when calculated we get toff = 4 ton.
Now the waveform is confined between 20 v to 70 v as it is stated that the base line is 20v and peak to peak is 50v.
avg = (1/T)*[(70*ton+ 20*toff)], where T=ton+toff.
Calculate it and you will get 30 v. Hope it will help someone.
(ton/(ton+toff)) = 0.2, when calculated we get toff = 4 ton.
Now the waveform is confined between 20 v to 70 v as it is stated that the base line is 20v and peak to peak is 50v.
avg = (1/T)*[(70*ton+ 20*toff)], where T=ton+toff.
Calculate it and you will get 30 v. Hope it will help someone.
Raghu said:
1 decade ago
20+50*0.2 = 30.
Nagaraj said:
10 years ago
50-20 = 30.
(1)
Vladimir said:
9 years ago
As per my logic, 50(0.6) = 30.
Shadan said:
8 years ago
The Avg voltage = 0.637*50= 31.000.
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