# Electronics - Alternating Current and Voltage - Discussion

Discussion Forum : Alternating Current and Voltage - General Questions (Q.No. 6)
6.
What is the instantaneous peak voltage at 250° on a 6 V peak sine wave?
+5.64 V
–5.64 V
+26.13 V
–26.13 V
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
11 comments Page 1 of 2.

Ancy said:   4 years ago
Because θ =wt.

Ajit said:   4 years ago
How wt is equal to 250? Please explain.

Sam said:   7 years ago
Formula = Io sin2^ft.
F = 250/2.
= 6sin 250,
= 5.638 = -5.64,
(1)

VamsI said:   8 years ago
Excellent explanation. Thank you all.

Ajinkya said:   8 years ago
Thank you, all for your answer and explanation.

PrivUsr said:   8 years ago
The instantaneous values of a sinusoidal waveform is given as:

Vi = Vmax Sin θ.
= 6 Sin 250°
= 6(-.94).
= -5.64 V.

Arya said:   9 years ago
Please give the answer.

Subash Pakhrin said:   10 years ago
V = Vmax*Sin(wt).

Where wt is angular frequency in this case is 250 so,
V = 6 * sin(250).

Therefore V = -5.64.

Yash said:   1 decade ago
According to the formula, let

V [instantaneous] = V[peak]sin[wt].

6*sin[256].

6*-0.097.

-5.64.

Ram said:   1 decade ago
V=Vm Sin wt so, V=6,wt=250
V=6 sin250
V=-5.64v

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