Here we have a transformer with 10 times as many windings in the primary (on the right) than in the secondary (on the left). As a result, the voltage in secondary is 1/10th the primary voltage. (It's not exactly 12V because of resistance in the primary and imperfect coupling between the two windings.)
If the secondary were shorted (the resistor replaced with a wire), the primary current would be much greater, and the secondary current would be 10 times the primary current. -- Credits: Mr. Paul Falstad.
|Tracy said: (Aug 1, 2011)|
|How does it work?|
|Suguna T D said: (Oct 21, 2016)|
|Always N1/N2=n turns ratio right ?|
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