Electronics and Communication Engineering - Signals and Systems - Discussion
Discussion Forum : Signals and Systems - Section 4 (Q.No. 24)
24.
A 1 kHz sinusoidal signal is ideally sampled at 1500 samples/sec and the sampled signal is passed through an ideal low pass filter with cut off frequency 800 Hz. The output signal has the frequency.
Answer: Option
Explanation:
Given fs = 1500 Hz ⇒ fm = 750 Hz.
The given signal frequency is 1 kHz.
The sampled frequency is 2.5 kHz, 0.5 kHz, But cut off frequency is 800 Hz or 0.8 kHz.
Therefore only 0.5 kHz will pass.
Discussion:
7 comments Page 1 of 1.
Dereje Gizaw said:
3 months ago
Anyone explain the answer in detail.
Beulah Durairaj said:
4 years ago
Given:
fm= 1 KHz, fs= 1500, 1.5KHz.
For output signals = ( fs+fm), (fs-fm)
= (1.5+1) , (1.5-1)
= (2.5), (0.5).
Given fc = 800Hz = 0.8 KHz.
So, consider the output signal as 0.5 KHz.
fm= 1 KHz, fs= 1500, 1.5KHz.
For output signals = ( fs+fm), (fs-fm)
= (1.5+1) , (1.5-1)
= (2.5), (0.5).
Given fc = 800Hz = 0.8 KHz.
So, consider the output signal as 0.5 KHz.
(1)
BOJARAJAN said:
5 years ago
Sampled frequencies are fs + fm and fs-fm.
Therefore, the Answer is option B.
Therefore, the Answer is option B.
Karthi said:
6 years ago
How? Please explain.
Rama said:
6 years ago
Why don't we consider 0.75, it also lies within the range of 0.5 to 0.8.
Rambabu k said:
7 years ago
Sampled frequency fs=2fm.
Sambasivam said:
8 years ago
How to calculate the value of sampled frequency? Can you please explain?
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