Electronics and Communication Engineering - Signals and Systems - Discussion
Discussion Forum : Signals and Systems - Section 1 (Q.No. 1)
1.
What about the stability of system in 
Answer: Option
Explanation:
ROC include the unit circle hence it is stable.
Discussion:
50 comments Page 4 of 5.
Sridevi said:
8 years ago
Please give the explanation of the answer clearly.
Sk jha said:
8 years ago
I think the system is unstabe.
It's me . . . said:
8 years ago
System is stable.
For the system to be stable, the unit circle should lie between ROC.
Hence unit circle lie between 0.4 and 2.
For the system to be stable, the unit circle should lie between ROC.
Hence unit circle lie between 0.4 and 2.
Dhivya said:
8 years ago
Can anyone please explain how to solve these type of problem?
Iram said:
8 years ago
H(z) = (-3/4z)/(z-0.4) + (16/5z)/(z-2) this is final transfer function. by sketching its ROC it can be seen that pole at 2 Roc lie outside unity circle while pole at 0.4 Roc includes unity circle by expanding in an outward direction.
So, the system is stable.
So, the system is stable.
RAM said:
8 years ago
Can't understand please can anyone explain it?
D.SIVASAMY said:
8 years ago
System is unstable because pole 2 locating outside the unit circle.
Meena said:
8 years ago
I don't understand. Please explain in detail.
Harshith said:
7 years ago
It is unstable when z>2.
Ramasubramanian said:
7 years ago
The system is unstable since the pole z=2 lies outside the UNIT circle.
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